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BMP文件头定义:
WORD 两个字节 16bit
DWORD 四个字节 32bit
package main import ( "encoding/binary" "fmt" "os" ) func main() { file, err := os.Open("tim.bmp") if err != nil { fmt.Println(err) return } defer file.Close() //type拆成两个byte来读 var headA, headB byte //Read第二个参数字节序一般windows/linux大部分都是LittleEndian,苹果系统用BigEndian binary.Read(file, binary.LittleEndian, &headA) binary.Read(file, binary.LittleEndian, &headB) //文件大小 var size uint32 binary.Read(file, binary.LittleEndian, &size) //预留字节 var reservedA, reservedB uint16 binary.Read(file, binary.LittleEndian, &reservedA) binary.Read(file, binary.LittleEndian, &reservedB) //偏移字节 var offbits uint32 binary.Read(file, binary.LittleEndian, &offbits) fmt.Println(headA, headB, size, reservedA, reservedB, offbits) }
执行结果
66 77 196662 0 0 54
使用结构体方式
package main import ( "encoding/binary" "fmt" "os" ) type BitmapInfoHeader struct { Size uint32 Width int32 Height int32 Places uint16 BitCount uint16 Compression uint32 SizeImage uint32 XperlsPerMeter int32 YperlsPerMeter int32 ClsrUsed uint32 ClrImportant uint32 } func main() { file, err := os.Open("tim.bmp") if err != nil { fmt.Println(err) return } defer file.Close() //type拆成两个byte来读 var headA, headB byte //Read第二个参数字节序一般windows/linux大部分都是LittleEndian,苹果系统用BigEndian binary.Read(file, binary.LittleEndian, &headA) binary.Read(file, binary.LittleEndian, &headB) //文件大小 var size uint32 binary.Read(file, binary.LittleEndian, &size) //预留字节 var reservedA, reservedB uint16 binary.Read(file, binary.LittleEndian, &reservedA) binary.Read(file, binary.LittleEndian, &reservedB) //偏移字节 var offbits uint32 binary.Read(file, binary.LittleEndian, &offbits) fmt.Println(headA, headB, size, reservedA, reservedB, offbits) infoHeader := new(BitmapInfoHeader) binary.Read(file, binary.LittleEndian, infoHeader) fmt.Println(infoHeader) }
执行结果:
66 77 196662 0 0 54
&{40 256 256 1 24 0 196608 3100 3100 0 0}
补充:golang(Go语言) byte/[]byte 与 二进制形式字符串 互转
效果
把某个字节或字节数组转换成字符串01的形式,一个字节用8个”0”或”1”字符表示。
比如:
byte(3) –> “00000011” []byte{1,2,3} –> “[00000001 00000010 00000011]” “[00000011 10000000]” –> []byte{0x3, 0x80}
开源库 biu
实际上我已经将其封装到一个开源库了(biu),其中的一个功能就能达到上述效果:
//byte/[]byte -> string bs := []byte{1, 2, 3} s := biu.BytesToBinaryString(bs) fmt.Println(s) //[00000001 00000010 00000011] fmt.Println(biu.ByteToBinaryString(byte(3))) //00000011 //string -> []byte s := "[00000011 10000000]" bs := biu.BinaryStringToBytes(s) fmt.Printf("%#v\n", bs) //[]byte{0x3, 0x80}
代码实现
const ( zero = byte('0') one = byte('1') lsb = byte('[') // left square brackets rsb = byte(']') // right square brackets space = byte(' ') ) var uint8arr [8]uint8 // ErrBadStringFormat represents a error of input string's format is illegal . var ErrBadStringFormat = errors.New("bad string format") // ErrEmptyString represents a error of empty input string. var ErrEmptyString = errors.New("empty string") func init() { uint8arr[0] = 128 uint8arr[1] = 64 uint8arr[2] = 32 uint8arr[3] = 16 uint8arr[4] = 8 uint8arr[5] = 4 uint8arr[6] = 2 uint8arr[7] = 1 } // append bytes of string in binary format. func appendBinaryString(bs []byte, b byte) []byte { var a byte for i := 0; i < 8; i++ { a = b b <<= 1 b = 1 switch a { case b: bs = append(bs, zero) default: bs = append(bs, one) } b <<= 1 } return bs } // ByteToBinaryString get the string in binary format of a byte or uint8. func ByteToBinaryString(b byte) string { buf := make([]byte, 0, 8) buf = appendBinaryString(buf, b) return string(buf) } // BytesToBinaryString get the string in binary format of a []byte or []int8. func BytesToBinaryString(bs []byte) string { l := len(bs) bl := l*8 + l + 1 buf := make([]byte, 0, bl) buf = append(buf, lsb) for _, b := range bs { buf = appendBinaryString(buf, b) buf = append(buf, space) } buf[bl-1] = rsb return string(buf) } // regex for delete useless string which is going to be in binary format. var rbDel = regexp.MustCompile(`[^01]`) // BinaryStringToBytes get the binary bytes according to the // input string which is in binary format. func BinaryStringToBytes(s string) (bs []byte) { if len(s) == 0 { panic(ErrEmptyString) } s = rbDel.ReplaceAllString(s, "") l := len(s) if l == 0 { panic(ErrBadStringFormat) } mo := l % 8 l /= 8 if mo != 0 { l++ } bs = make([]byte, 0, l) mo = 8 - mo var n uint8 for i, b := range []byte(s) { m := (i + mo) % 8 switch b { case one: n += uint8arr[m] } if m == 7 { bs = append(bs, n) n = 0 } } return }
以上为个人经验,希望能给大家一个参考,也希望大家多多支持。如有错误或未考虑完全的地方,望不吝赐教。
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